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H.C.F and L.C.M Aptitude Test Paper 5


21) The LCM of two prime number x and y is 161. If x>y, find the value of 15y-7x.

  1. -32
  2. -56
  3. 38
  4. 74

Answer: B

Explanation:

Note: The HCF of two prime numbers = 1

LCM/HCF =161/1 =161
161=7 * 23
The ratio of numbers: 7: 23
Hence, the expression gives15 * 7 - 7 * 23 = -56


22) Find the smallest digit that will leave same remainder 4 in each case when divided by 12, 15, 20, and 54.

  1. 454
  2. 540
  3. 544
  4. 450

Answer: C

Explanation:

Take LCM of 12, 15, 20, and 54. It will be = 540.

ATQ, the remainder in each case = 4.

Hence, the required number = 540+4 = 544.


23) What is the number nearest to 10000 which is exactly divisible by 3, 4, 5, 6, 7, and 8?

  1. 9956
  2. 10080
  3. 10096
  4. 9240

Answer: B

Explanation:

Take LCM of 3, 4, 5, 6, 7, and 8. It will be = 840.

Now, 10000/840 = 760 (remainder).

840 - 760 = 80. If we add 80 in the given number, the number is exactly divisible by 840.

So, the required number is 10080.



H.C.F and L.C.M Aptitude Test Paper 1
H.C.F and L.C.M Aptitude Test Paper 2
H.C.F and L.C.M Aptitude Test Paper 3
H.C.F and L.C.M Aptitude Test Paper 4
H.C.F and L.C.M Aptitude Concepts





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