Aptitude Pipes and Cisterns Test Paper 2

Correct Option (A)

Answer with explanation:

Part of the tank filled by the inlet in one hour =
Part of the tank emptied by the outlet in one hour =
Net part of the tank filled in one hour = -

part of the tank is filled in one hour

∴ The whole tank will be filled in 24 hours.

Solution 2:
Apply formula; =

X = 6 hours

Y = 8 hours
∴ Required time = = 24 hours

Correct answer; option (C)

Answer with explanation:

Capacity of each bucket = 12 liters

20 buckets can fill the tank. So, capacity of tank = 20 * 12= 240 liters

New capacity of bucket = 10 liters

So, 10 liters can be poured into the tank by one bucket

Correct answer; option (C)

Answer with explanation:

Let the first pipe fill the reservoir in X minutes

So, the second pipe will fill the reservoir in (X+10) minutes

As per question;

12X +120 + 12X = X² + 10X

X² +10X 24X -120 = 0

X² 14X -120 =0

X² - 20X+6X 120=0

X(X-20) +6(X-20) =0

(X+6) (X-20) = 0

X = 20

∴Second pipe will fill the reservoir in 20 + 10= 30 minutes

Correct answer; option (D)

Answer with explanation:

Apply formula used in work and time problems; M1D1T1W2 = M2D2T2W1

M1= 25 outlets, D1=10 days, T1= 6 hours/day, W2 = to fill the reservoir

M2= 15 outlets, D2=? T2 = 4 hours/day, W1= to fill the reservoir

W1=W2

So we have; M1D1T1= M2D2T2

25*10*6=15*D2*4

1500 = 60 * D2

Correct answer; option (A)

Answer with explanation:

Part of the tank filled by pipe A in one minute=

Part of the tank filled by A+B in one minute =

Part of the tank filled by B alone =

∴ Pipe B will fill the whole tank in 24 minutes.

Solution 2:

X= 12 minutes

Y=?

As per question;

12Y= 8Y+96

4Y= 96

Y = 24 minutes