Speed Time and Distance Test Paper 416) The ratio between the speeds of a bus and car is 8:6. If the car travels 200 km in 2 hours, find the speed of the bus.
The Correct answer is (B) Answer with explanation: Let the speed of bus and car is 8X and 6X. Speed of car=^{200}⁄_{2}→100 km/hr So, 6X= 100 X=^{100}⁄_{6}→ (50 )/3 km/hr Speed of bus= 8X → 8 *^{50}⁄_{3}=^{400}⁄_{3}= 133.3 km/hr (Option B) 17) A man travels first 150 km of his journey at 80 km/hr. Due to bad weather he travels the next 150 km of his journey at 60 km/hr. What is his average speed for the first 300 km of his journey?
The Correct answer is (D) Answer with explanation: Total distance = 300 km The total time taken to cover the first 300 km is the sum of the time taken to cover the first 150 km and the next 150 km. 18) A car moving with^{6}⁄_{9} of its actual speed covers 50 km in 1 hour 40 min. What is the actual speed of the car?
The Correct answer is (C) Answer with explanation: Let the actual speed of the car = X km/hr
∴ the car is moving at X *^{6}⁄_{9}km/hr
Distance = 50 km
Time taken to cover 50 km= 1 hour 40 minutes →1+^{40}⁄_{60}= 5/3 hrs
Distance = Speed x Time
50 = X *^{6}⁄_{9}*^{5}⁄_{3}
19) The circumference of a jogging track is 735 m. Peter and Tom start walking from the same point at the same time in opposite direction. If they are walking at 6 km/hr and 8 km/hr respectively, after how much time they will meet?
The Correct answer is (C) Answer with explanation: Let both of them meet after time T Distance travelled by Peter = Speed x Time Distance travelled by Tom = Speed x Time Now, the sum of the distances covered by them would be equal to the circumference of the track. 35 T = 735 * 9 35 T = 6615 T =^{6615}⁄_{35}= 189 seconds Time in minutes =^{189}⁄_{60} = 3.15 minutes (Option C) 20) A man can swim at 10 km/hr in still water. It takes him twice as much time to reach the destination when he swims up the river as it takes when he swims down the river. At what speed the river is flowing?
The Correct answer is (A) Answer with explanation: Let the speed of the river = X km/hr So, speed of man with the flow (downward speed) = 10 + X Similarly speed of man against the flow (upward speed) = 10  X Let the man covers a distance Y. So time taken to cover the distance Y when he swims up the river would be double of the time taken to cover the distance Y when he swims down the river. So, ^{Y}⁄_{10X} = 2 *^{Y}⁄_{10+X} 10Y + XY = 20Y 2XY XY + 2XY = 20Y  10 Y 3XY= 10Y 3X =^{10Y}⁄_{Y} 3X = 10 X =^{10}⁄_{3}km/hr (Option A) Speed Time and Distance Aptitude Test Paper 1 Speed Time and Distance Aptitude Test Paper 2 Speed Time and Distance Aptitude Test Paper 3 Speed Time and Distance Aptitude Test Paper 4 Speed Time and Distance Aptitude Test Paper 5 Speed Time and Distance Concepts
Next TopicSpeed Time and Distance Test Paper 5

Ansible
Mockito
Talend
Azure
SharePoint
Powershell
Kali Linux
OpenCV
Kafka
Pandas
Joomla
Reinforcement