# Speed Time and Distance Test Paper 4

16) The ratio between the speeds of a bus and car is 8:6. If the car travels 200 km in 2 hours, find the speed of the bus.

1. 131.3 km/hr
2. 133.3 km/hr
3. 135.3 km/hr
4. 137.3 km/hr

Let the speed of bus and car is 8X and 6X. Speed of car=2002→100 km/hr

So, 6X= 100

X=1006→ (50 )/3 km/hr

Speed of bus= 8X → 8 *503=4003= 133.3 km/hr (Option B)

17) A man travels first 150 km of his journey at 80 km/hr. Due to bad weather he travels the next 150 km of his journey at 60 km/hr. What is his average speed for the first 300 km of his journey?

1. 60.6 km/hr
2. 63.6 km/hr
3. 66.6 km/hr
4. 68.6 km/hr Total distance = 300 km

The total time taken to cover the first 300 km is the sum of the time taken to cover the first 150 km and the next 150 km. 18) A car moving with69 of its actual speed covers 50 km in 1 hour 40 min. What is the actual speed of the car?

1. 65 km/hr
2. 70 km/hr
3. 45 km/hr
4. 80 km/hr Let the actual speed of the car = X km/hr

∴ the car is moving at X *69km/hr

Distance = 50 km

Time taken to cover 50 km= 1 hour 40 minutes →1+4060= 5/3 hrs

Distance = Speed x Time

50 = X *69*53 19) The circumference of a jogging track is 735 m. Peter and Tom start walking from the same point at the same time in opposite direction. If they are walking at 6 km/hr and 8 km/hr respectively, after how much time they will meet?

1. 3 minutes
2. 3.12 minutes
3. 3.15 minutes
4. 4 minutes

Let both of them meet after time T

Distance travelled by Peter = Speed x Time Distance travelled by Tom = Speed x Time Now, the sum of the distances covered by them would be equal to the circumference of the track. 35 T = 735 * 9

35 T = 6615

T =661535= 189 seconds

Time in minutes =18960 = 3.15 minutes (Option C)

20) A man can swim at 10 km/hr in still water. It takes him twice as much time to reach the destination when he swims up the river as it takes when he swims down the river. At what speed the river is flowing?

1. 103 km/hr
2. 82km/hr
3. 117km/hr
4. 105 km/hr

Let the speed of the river = X km/hr

So, speed of man with the flow (downward speed) = 10 + X

Similarly speed of man against the flow (upward speed) = 10 - X

Let the man covers a distance Y.

So time taken to cover the distance Y when he swims up the river would be double of the time taken to cover the distance Y when he swims down the river. So, Y10-X = 2 *Y10+X

10Y + XY = 20Y -2XY

XY + 2XY = 20Y - 10 Y

3XY= 10Y

3X =10YY

3X = 10

X =103km/hr (Option A)

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Speed Time and Distance Concepts

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