Aptitude Time and Work Test Paper 26) A, B, C can do a job in 10, 20 and 40 days respectively. In how many days A can complete the job if he is assisted by B and C on every third day?
The Correct answer is (A) Explanation: A's one day work = B's one day work = C's one day work = (A+B+C)'s one day work = Work done in three days will be the sum of A's twoday work and (A+B+C)'s one day work. A's twoday work = Therefore, the work is done in three days = 3/8 part of the job is done in 3 days. The entire job will be done by A in = 3 x 7) If 5 men can colour 50meter long cloth in 5 days, in many days 4 men can color a 40meter long cloth?
The Correct answer is (A) Explanation: 5 men colour 50meter long cloth in 5 days. 1 man will colour= 10meter long cloth in five days. So, in one day one man can colour= 2meter long cloth. Now, as per question 4 men are supposed to colour the 40meter long cloth. One man has to colour the = 10 meter cloth For 2meter long cloth one man takes 1 day So, to paint 10meter long cloth he will take = As, 4 men are working together so 40 m long cloth will be coloured in 5 days Quicker method: Apply formula: M1D1W2 = M2D2W1 5*5*40 = 4*D2*50 D2= 8) If 4 men can finish 4 times of a work in 4 days, in how many days 6 men can finish the 6 times of same work ?
The Correct answer is (B) Explanation: 4 men can finish 4 times of work in four days. Therefore, one man can finish the one time of work in four days. So, 6 men will finish the six times of work in the same time (4 days) Quicker method: Apply formula: M1D1W2 = M2D2W1 Let the work be X Work done by 4 men, W1 = 4X Work done by 6 men, W2 = 6X 4*4*6X = 6*D2*4X 96X = D2 *24X D2= 4 days 9) A can do a piece of work in 10 days. B is 50% more efficient than A. In how many days B alone can do the same job?
The Correct answer is (B) Explanation: B is 50%more efficient than A so he will take less time to do a piece of work. Therefore, the ratio of the time taken by A and B = Let B takes X days to do the job. 3X =20 X = 6.6 days 10) A can do a job in 30 days. B alone can do the same job in 20 days. If A starts the work and joined by B after 10 days, in how many days the job will be done?
The Correct answer is (D) Explanation: A's one day work = A's tenday work = So the remaining work would be = B's one day work = A and B's one day work = of the job will be done by them in one day. So, the remaining job= 8 days Therefore, the total number of days required to do the job would be = 10 + 8 = 18 days Aptitude Time and Work Test Paper 1 Aptitude Time and Work Test Paper 3 Aptitude Time and Work Test Paper 4 Aptitude Time and Work Test Paper 5 Aptitude Time and Work Test Paper 6 Aptitude Time and Work Test Paper 7 Aptitude Time and Work Test Paper 8 Aptitude Time and Work Test Paper 9 Time and Work Concepts
Next TopicTime and Work Test Paper 3

Ansible
Mockito
Talend
Azure
SharePoint
Powershell
Kali Linux
OpenCV
Kafka
Pandas
Joomla
Reinforcement