Aptitude Time and Work Test Paper 2


6) A, B, C can do a job in 10, 20 and 40 days respectively. In how many days A can complete the job if he is assisted by B and C on every third day?

  1. 8 days
  2. 7 days
  3. 9 days
  4. 6 days

The Correct answer is (A)

Explanation:

A's one day work =Apti Time and work 56

B's one day work =Apti Time and work 57

C's one day work =Apti Time and work 58

(A+B+C)'s one day work =Apti Time and work 59

Work done in three days will be the sum of A's two-day work and (A+B+C)'s one day work.

A's two-day work =Apti Time and work 60

Therefore, the work is done in three days =Apti Time and work 61

3/8 part of the job is done in 3 days.

The entire job will be done by A in = 3 x Apti Time and work 62


7) If 5 men can colour 50-meter long cloth in 5 days, in many days 4 men can color a 40-meter long cloth?

  1. 5 days
  2. 6 days
  3. 4 days
  4. 3 days

The Correct answer is (A)

Explanation:

5 men colour 50-meter long cloth in 5 days.

1 man will colourApti Time and work 63= 10-meter long cloth in five days.

So, in one day one man can colourApti Time and work 64= 2-meter long cloth.

Now, as per question 4 men are supposed to colour the 40-meter long cloth.

One man has to colour the Apti Time and work 65= 10 meter cloth

For 2-meter long cloth one man takes 1 day

So, to paint 10-meter long cloth he will take =Apti Time and work 66

As, 4 men are working together so 40 m long cloth will be coloured in 5 days

Quicker method:

Apply formula: M1D1W2 = M2D2W1

5*5*40 = 4*D2*50

D2=Apti Time and work 67


8) If 4 men can finish 4 times of a work in 4 days, in how many days 6 men can finish the 6 times of same work ?

  1. 3 days
  2. 4 days
  3. 5 days
  4. 6 days

The Correct answer is (B)

Explanation:

4 men can finish 4 times of work in four days.

Therefore, one man can finish the one time of work in four days.

So, 6 men will finish the six times of work in the same time (4 days)

Quicker method:

Apply formula: M1D1W2 = M2D2W1

Let the work be X

Work done by 4 men, W1 = 4X

Work done by 6 men, W2 = 6X

4*4*6X = 6*D2*4X

96X = D2 *24X

D2= 4 days


9) A can do a piece of work in 10 days. B is 50% more efficient than A. In how many days B alone can do the same job?

  1. 6.2 days
  2. 6.6 days
  3. 7 days
  4. 7.2 days

The Correct answer is (B)

Explanation:

B is 50%Apti Time and work 68more efficient than A so he will take less time to do a piece of work.

Therefore, the ratio of the time taken by A and B =Apti Time and work 69

Let B takes X days to do the job.

Apti Time and work 70

3X =20

X = 6.6 days


10) A can do a job in 30 days. B alone can do the same job in 20 days. If A starts the work and joined by B after 10 days, in how many days the job will be done?

  1. 15 days
  2. 16 days
  3. 17 days
  4. 18 days

The Correct answer is (D)

Explanation:

A's one day work =Apti Time and work 71

A's ten-day work =Apti Time and work 72

So the remaining work would be =Apti Time and work 73

B's one day work =Apti Time and work 74

A and B's one day work =Apti Time and work 75

Apti Time and work 76of the job will be done by them in one day.

So, the remaining jobApti Time and work 77= 8 days

Therefore, the total number of days required to do the job would be = 10 + 8 = 18 days



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