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GATE 2018 CS Set 3

57) A __________ investigation can sometimes yield new facts, but typically organized once are more successful.

  1. Meandering
  2. Timely
  3. Consistent
  4. Systematic

Answer: A

Explanation:

The right choice is meandering. Because meandering means "proceeding in a convoluted or undirected fashion" and all other options contradicts the meaning of organized (ordered).


58) The area of a square is 'd'. What is the area of the circle which has the diagonal of the square as its diameter?

  1. πd
  2. πd2
  3. (1/4) πd2
  4. (1/2)πd

Answer: D

Explanation:

Area of square = πr2
i.e.
     a2 = d
Side of the square (a) = √d
Diagonal of the square = √(a2 + a2) = √((√d)2 + (√d)2) = √(d + d) = √(2d)
Diameter of the circle = Diagonal of the square = √(2d)
Radius of the circle = √(2d) / 2

Now,
Area of the circle = πr2
= π* (√(√(2d) / 2)2
= π* 2*d / 2* 2
= 1/2)πd


59) What would be the smallest natural number which when divided either by 20 or by 42 or by 76 leaves a remainder 7 in each case is?

  1. 3047
  2. 6047
  3. 7987
  4. 63847

Answer: C

Explanation:

Let the number be N.

ATQ,

N divided by 20, 42 or 76 gives the remainder 7 in each case. In other words, (N-7) is completely divisible by the given number 20, 42 & 76.

So, we need to calculate the least common multiple of 20, 42, 76.

i.e.

(?-7) = ???(20,42,76)

LCM of 20 = 2 * 2 *5
LCM of 42 = 2 * 3 * 7
LCM of 76 = 2 * 2 * 19
(20,42,76) = 2 * 2 * 5 * 3 * 7 * 19 => 7980

Hence,
=> (?-7) = 7980
=> N = 7980 + 7
=> N = 7987


60) What is the missing number in the following sequence?

2, 12, 60, 240, 720, 1440, .... 0

  1. 2880
  2. 1440
  3. 720
  4. 0

Answer: B

Explanation:

2*6=12, 12*5=60, 60*4=240, 240*3=720, 720*2=1440, 1440*1=1440, 1440*0

The series begins with 2. Multiply the first term with 6 and get second term 12. Multiply the second term with 5 and get third term 60. Multiply the third term with 4 and get fourth term 340. Multiply the fourth term with 3 and get fifth term 720. Multiply the fifth term with 2 and get fifth term 1440. Multiply the sixth term with 1 and get 1440 again. In last we multiply it with 0 and get zero(0).


61) In appreciative of social improvement completed in a town, a wealthy philanthropist decided to give gift of Rs. 750 to each male senior citizen and Rs. 1000 for female senior citizens. There are total 300 senior citizens and th 8/9th of total men and 2/3rd of total women claimed the gift. What is amount of money philanthropist paid?

  1. 15000
  2. 200000
  3. 115000
  4. 151000

Answer: B

Explanation:

Let no. of senior male be x and female be y
x+y = 300
so, y = 300 - x
Total money paid by philanthropist = 750 * 8/9 * x + 1000 * 2/3 * (300 - x)
= 6000x/9 + 2 * 105 - 2000x/3
= 2000x/3 - 2000x/3 + 2 * 105
= 2*105
= 200000


62) If pqr ≠ 0 and p-x = 1/q, q-y = 1/r, r-z = 1/p, what is the value of the product xyz?

  1. -1
  2. 1 / pqr
  3. 1
  4. pqr

Answer: C

Given,

P-x = 1/q
q--y- = 1/r
r--z- = 1/p

Now, Take log on both the side, we get

x log p = log q

=> x = log q / log p

y log q = log r

=> y = log r / log q

z log r = log p

=> z = log p / log r

So, xyz = log q / log p * log r / log q * log p / log r = 1

Therefore option (C) will be the right answer.


63) In a party, 60% of the invited guests are male and 40% are female. If 80% of the invited guests attended the party and if all the invited female guests attended, what would be the ratio of males to females among the attendees in the party?

  1. 2:3
  2. 1:1
  3. 3:2
  4. 2:1

Answer: B

Explanation:

Suppose 100 people are invited in a party.

Given,
men invited = 60, and
women invited = 40
Therefore ATQ,
During the party only 80 people came, and all women attended => 80
               = > 40 + men

Therefore, men = 40
Hence,
The ratio of males to females = 1:1


64) In the figure below, ∠DEC+∠BFC is equal to _______ .

GATE CS Set 3

  1. ∠ BCD - ∠ BAD
  2. ∠ BAD + ∠ BCF
  3. ∠ BAD + ∠ BCD
  4. ∠ CBA + ∠ ADC

Answer: A

Explanation:

According to the triangle property that "the exterior angle of a triangle is the sum of the two opposite interior angle."

GATE CS Set 3

Therefore, ∠z = ∠x + ∠y ----->1
Similarly,
    ∠y = ∠a + ∠b ------->2
By subsituting 2 in 1 we get,
   ∠Z = ∠x + ∠a + ∠b.
Now, ∠Z = ∠BCD
     ∠b = ∠BAD.
∠BCD - ∠BAD = ∠Z - ∠b
       = ∠x + ∠a + ∠b - ∠b
       = ∠x + ∠a
       = ∠DEC + ∠BFC


65) A six sided unbiased die with four green faces and two red faces is rolled seven times. Which of the following combinations is the most likely outcome of the experiment?

  1. Three green faces and four red faces.
  2. Four green faces and three red faces.
  3. Five green faces and two red faces.
  4. Six green faces and one red face

Answer: C

Explanation:

The probability of each options are:
A = P(3G,4R) = 7C3 * (4/6)3(2/6)4
B = P(4G,3R) = 7C4 * (4/6)4(2/6)3
C = P(5G,2R) = 7C5 * (4/6)5(2/6)2
D = P(6G,1R) = 7C6 * (4/6)6(2/6)1

From the above we can easily eliminate the option A which has more number of red faces.

C/B=7C5 / 7C4 * 4/6 * 6/2 = 3/5 * 2 > 1.

So, C>B.

C/D = 7C5 / 7C6 * 6/4 * 2/6 = 21/7 * 0.5 > 1.

So, C>D.
Hence, C is the most favourable outcome.


GATE 2018 CS Set 3-1
GATE 2018 CS Set 3-2
GATE 2018 CS Set 3-3
GATE 2018 CS Set 3-4
GATE 2018 CS Set 3-5
GATE 2018 CS Set 3-6
GATE 2018 CS Set 3-7
GATE Introduction
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