# Insertion into circular singly linked list at the end

There are two scenario in which a node can be inserted in circular singly linked list at beginning. Either the node will be inserted in an empty list or the node is to be inserted in an already filled list.

• Firstly, allocate the memory space for the new node by using the malloc method of C language.

In the first scenario, the condition head == NULL will be true. Since, the list in which, we are inserting the node is a circular singly linked list, therefore the only node of the list (which is just inserted into the list) will point to itself only. We also need to make the head pointer point to this node. This will be done by using the following statements.

In the second scenario, the condition head == NULL will become false which means that the list contains at least one node. In this case, we need to traverse the list in order to reach the last node of the list. This will be done by using the following statement.

At the end of the loop, the pointer temp would point to the last node of the list. Since, the new node which is being inserted into the list will be the new last node of the list. Therefore the existing last node i.e. temp must point to the new node ptr. This is done by using the following statement.

The new last node of the list i.e. ptr will point to the head node of the list.

In this way, a new node will be inserted in a circular singly linked list at the beginning.

## Algorithm

• Step 1: IF PTR = NULL
•   Write OVERFLOW
Go to Step 1
[END OF IF]

• Step 2: SET NEW_NODE = PTR
• Step 3: SET PTR = PTR -> NEXT
• Step 4: SET NEW_NODE -> DATA = VAL
• Step 5: SET NEW_NODE -> NEXT = HEAD
• Step 6: SET TEMP = HEAD
• Step 7: Repeat Step 8 while TEMP -> NEXT != HEAD
• Step 8: SET TEMP = TEMP -> NEXT
• [END OF LOOP]

• Step 9: SET TEMP -> NEXT = NEW_NODE
• Step 10: EXIT