Java Byte parseByte() method

The parseByte() method of Java Byte class parses the string argument as a signed decimal. All the characters in the String should be decimal digits, except the first character which can be an ASCII minus or plus sign.

The second parameter parses the specified string argument as a signed byte in the specified radix.

Syntax:

public static byte parseByte(String s) throws NumberFormatException 
public static byte parseByte(String s, int radix) throws NumberFormatException

Parameters:

The parameters 's' and 'radix' represent the string to be parsed and the radix to be used while parsing s.

Throws

The parseByte() method throws:

NumberFormatException- if the string does not contain a parsable byte.

Return Value

This method returns the byte value represented by the argument in decimal.

Example 1

public class JavaByteParseByteExample1 {
    public static void main(String[] args) {
        String str="-8";
        int val=Byte.parseByte(str);
        System.out.println(val);
    }
}

Test it Now

Output:

-8

Example 2

public class JavaByteParseByteExample2 {
    public static void main(String[] args) throws NumberFormatException {
        String str="67";
        //throws an exception if the radix is less than zero
        int radix=0;
        int val=Byte.parseByte(str,radix);
        System.out.println(val);
    }
}

Test it Now

Output:

Exception in thread "main" java.lang.NumberFormatException: radix 0 less than Character.MIN_RADIX
	at java.lang.Integer.parseInt(Integer.java:546)
	at java.lang.Byte.parseByte(Byte.java:149)
	at com.JavaTpoint.JavaByteParseByteExample2.main(JavaByteParseByteExample2.java:8)

Example 3

public class JavaByteParseByteExample3 {
    public static void main(String[] args) throws NumberFormatException {
        //the string shout be a byte number
        String str="35";
        int radix=Character.MAX_RADIX;
        int val=Byte.parseByte(str,radix);
        System.out.println(val);
    }
}

Test it Now

Output:

Example 4

public class JavaByteParseByteExample4 {
    public static void main(String[] args) throws NumberFormatException {
        String str="null";
        int radix=Character.MAX_RADIX;
        System.out.println(radix);
        int val=Byte.parseByte(str,radix);
        System.out.println(val);
    }
}

Test it Now

Output:

36
Exception in thread "main" java.lang.NumberFormatException: Value out of range. Value:"null" Radix:36
	at java.lang.Byte.parseByte(Byte.java:151)
	at com.JavaTpoint.JavaByteParseByteExample4.main(JavaByteParseByteExample4.java:8)

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