Java Double longValue() Method

The longValue() method of Java Double class returns the value of this object as a long after narrowing the primitive values or by casting to type long.

Syntax

Parameters

Return value

The longValue() method returns the double value corresponding to this Double which has been converted to type long.

Example 1

public class Double_longValueMethodExample1{
    public static void main(String[] args) {
        double d1 = 655;
        Double d2 = new Double(d1);
        // return the long value of double object
        Long val1 = d2.longValue();
        System.out.println("1. "+"Long value for "+d1+" = "+val1);

        Double d3 = new Double(6575876985679.675);
        System.out.println("2. "+"Long value for "+d3+" = "+d3.longValue());
        //passing negative integer
        Double d4 = new Double(-86776985679.88675);
        System.out.println("3. "+"Long value for "+d4+" = "+d4.longValue());
    }
}

Test it Now

Output:

1. Long value for 655.0 = 655
2. Long value for 6.575876985679675E12 = 6575876985679
3. Long value for -8.677698567988675E10 = -86776985679

Example 2

import java.util.Scanner;

public class Double_longValueMethodExample2 {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Enter three numbers");
        System.out.print("1.");     Double d1 =scanner.nextDouble();
        System.out.print("2.");     Double d2 =scanner.nextDouble();
        System.out.print("3.");     Double d3 =scanner.nextDouble();
        //adding the long values
        Long val1= d1.longValue()+d2.longValue()+d3.longValue();
        System.out.println("1.Sum:     "+d1.longValue()+"+"+d2.longValue()+"+"+d3.longValue()+" = "+ val1);
        //
        Long val2= d1.longValue()*d2.longValue()*d3.longValue();
        System.out.println("1.Mul:     "+d1.longValue()+"*"+d2.longValue()+"*"+d3.longValue()+" = "+ val2);

    }
}

Test it Now

Output:

Enter three numbers
1.56.7568
2.422.087775
3.0.456454
1.Sum:     56+422+0 = 478
1.Mul:     56*422*0 = 0

Example 3

import java.util.Scanner;

public class Double_longValueMethodExample3 {
    public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
        System.out.println("Enter your annual income");
        Double d1 = scanner.nextDouble();
        Long val1 = d1.longValue() / 12;

         if (val1 < 30000 ) {
            Long l1= val1 + 2000;
            System.out.println("You got an increment of 5000.\nYour new monthly salary is:" +l1);
        }
        else if (val1 >30000 && val1< 80000) {
            Long l1= val1 + 5000;
            System.out.println("You got an increment of 5000.\nYour new monthly salary is:" +l1);
        } else if (val1 > 80000 && val1<100000) {
            Long l2= val1 + 8000;
            System.out.println("You got an increment of 8000.\nYour new monthly salary is:" + l2);
        } else {
            Long l3= val1 + 15000;
            System.out.println("You got an increment of 15000.\nYour new monthly salary is:" + l3);
        }
    }
}

Test it Now

Output:

Enter your annual income
486674.4553
You got an increment of 5000.
Your new monthly salary is:45556

Next TopicJava Double

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Java Double longValue() Method

Syntax

Parameters

Return value

Example 1

Example 2

Example 3

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