Java Math.decrementExact() method

The java.lang.Math.decrementExact() returns the argument decremented by one. It will throw an exception if the result overflows either int or long.

Syntax

public static int DecrementExact (int a) 
public static long decrementExact (long a)

Parameter

Return

If the argument is Integer.MIN_VALUE or Long.MIN_VALUE, it will throw an ArithmeticException.

Example 1

public class DecrementExactExample1
{
    public static void main(String[] args) 
    {
        int a = 830;
        System.out.println(Math.decrementExact(a));
    }
}

Test it Now

Output:

Example 2

public class DecrementExactExample2
{
    public static void main(String[] args) 
    {
        int a = -381;
        System.out.println(Math.decrementExact(a));
    }
}

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Output:

-382

Example 3

public class DecrementExactExample3
{
    public static void main(String[] args) 
    {
        int a = Integer.MIN_VALUE;
        // Input int overflow, Output ArithmeticException 
        System.out.println(Math.decrementExact(a));
    }
}

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Output:

Exception in thread "main" java.lang.ArithmeticException: integer overflow
	at java.lang.Math.decrementExact(Math.java:943)
	at decrementExactExample3.main(decrementExactExample3.java:7)

Example 4

public class DecrementExactExample4
{
    public static void main(String[] args) 
    {
        long a = Long.MIN_VALUE;
        // Input long overflow, Output ArithmeticException 
        System.out.println(Math.decrementExact(a));
    }
}

Test it Now

Output:

Exception in thread "main" java.lang.ArithmeticException: long overflow
	at java.lang.Math.decrementExact(Math.java:960)
	at decrementExactExample4.main(decrementExactExample4.java:7)

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