Java Math.incrementExact() method

The java.lang.Math.incrementExact() returns the argument incremented by one. It will throw an exception if the result overflows either int or long.

Syntax

public static int incrementExact (int a) 
public static long incrementExact (long a)

Parameter

Return

If the argument is Integer.MAX_VALUE or Long.MAX_VALUE, it will throw an ArithmeticException.

Example 1

public class IncrementExactExample1
{
    public static void main(String[] args) 
    {
        int a = 674;
        System.out.println(Math.incrementExact(a));
    }
}

Test it Now

Output:

Example 2

public class IncrementExactExample2
{
    public static void main(String[] args) 
    {
        int a = -53;
        System.out.println(Math.incrementExact(a));
    }
}

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Output:

-52

Example 3

public class IncrementExactExample3
{
    public static void main(String[] args) 
    {
        int a = Integer.MAX_VALUE;
        // Input integer overflow, Output ArithmeticException
        System.out.println(Math.incrementExact(a));
    }
}

Test it Now

Output:

Exception in thread "main" java.lang.ArithmeticException: integer overflow
	at java.lang.Math.incrementExact(Math.java:909)
	at incrementExactExample3.main(incrementExactExample3.java:7)

Example 4

public class IncrementExactExample4
{
    public static void main(String[] args) 
    {
        long a = Long.MAX_VALUE;
        // Input long overflow, Output ArithmeticException
        System.out.println(Math.incrementExact(a));
    }
}

Test it Now

Output:

Exception in thread "main" java.lang.ArithmeticException: long overflow
	at java.lang.Math.incrementExact(Math.java:926)
	at incrementExactExample4.main(incrementExactExample4.java:7)

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