Java Math.toIntExact() method

The java.lang.Math.toIntExact() returns the value of long argument. It will throw an exception if the result overflows either int or long.

Syntax

Parameter

Return

If the argument is Long.MAX_VALUE or Long.MIN_VALUE, it will throw an ArithmeticException.

Example 1

public class ToIntExactExample1
{
    public static void main(String[] args) 
    {
       long a = 230;
        System.out.println(Math.toIntExact(a));
    }
}

Test it Now

Output:

Example 2

public class ToIntExactExample2
{
    public static void main(String[] args) 
    {
        long a = -829;
        System.out.println(Math.toIntExact(a));
    }
}

Test it Now

Output:

-829

Example 3

public class ToIntExactExample3
{
    public static void main(String[] args) 
    {
        long a = Long.MAX_VALUE;
        System.out.println(Math.toIntExact(a));
    }
}

Test it Now

Output:

Exception in thread "main" java.lang.ArithmeticException: integer overflow
	at java.lang.Math.toIntExact(Math.java:1011)
	at toIntExactExample3.main(toIntExactExample3.java:6)

Example 4

public class ToIntExactExample4
{
    public static void main(String[] args) 
    {
        long a = Long.MIN_VALUE;
        System.out.println(Math.toIntExact(a));
    }
}

Test it Now

Output:

Exception in thread "main" java.lang.ArithmeticException: integer overflow
	at java.lang.Math.toIntExact(Math.java:1011)
	at toIntExactExample4.main(toIntExactExample4.java:6)

Next TopicJava Math

← prev next →