Modulus of two Float or Double Numbers

In this tutorial, we will learn how to determine the remainder of two floating-point numbers.

Examples:

Input: a = 9.7, b = 2.3 
Output: 0.5
Input: a = 36.5, b = 5.0 
Output: 1.5

C Program:

#include <stdio.h>
#include <math.h>

int main()
{
    int x = 10;
    int y = 3;

    float p = 10.23f;
    float q = 3.1f;

    double a = 123456789.10;
    double b = 1233.1;

        printf("remainder(%lf,%lf) = %lf\n", a, b, remainder(a, b));
        printf("remainder(%d,%d) = %lf\n", x, y, remainder(x, y));
         printf("remainder(%f,%f) = %lf\n", p, q, remainder(p, q));


    return 0;
}

Output:

remainder(123456789.100000,1233.100000) = 50.200000
remainder(10,3) = 1.000000
remainder(10.230000,3.100000) = 0.930000

C++ Program:

#include <bits/stdc++.h>
using namespace std;

double findingMod(double x, double y)
{
	double mod;
	if (x < 0)
		mod = -x;
	else
		mod = x;
	if (y < 0)
		y = -y;
	while (mod >= y)
		mod = mod - y;
	if (x < 0)
		return -mod;

	return mod;
}
int main()
{
	double x = 9.7, y = 2.3;
	cout << findingMod(x, y);
	return 0;
}

Output:

0.5

To find the modulus of two floating-point values, we can utilise the built-in fmod function.

C++ Program:

#include <bits/stdc++.h>
using namespace std;

int main()
{
	double x = 9.7, y = 2.3;
	cout << fmod(x, y);
	return 0;
}

Output:

0.5

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