Java Random nextInt() Method

The nextInt() method of Random class returns the next pseudorandom, uniformly distributed int value from the random number generator's sequence.

Syntax

Parameters

Return Value

The nextInt() method returns the next pseudorandom int value drawn from the random number generator's sequence.

Example 1

import java.util.Random;

public class JavaRandomNextIntExample1 {
public static void main(String[] args) {
        Random random = new Random();
//return the next pseudorandom integer value
Integer val = random.nextInt();
System.out.println("Random Integer value : "+val);
        Integer val1 = random.nextInt();
System.out.println("Random Integer value : "+val1);
    }
}

Test it Now

Output:

Random Integer value : -298063488
Random Integer value : 1400961289

Java Random nextInt() Method

The nextInt(int n) method of Random class returns a pseudorandom int value between zero (inclusive ) and the specified value(exclusive), drawn from the random number generator?s sequence.

Syntax

Parameters

n: It is the bound on the random number to be returned. It must be positive.

Return Value

The nextInt() method returns the next pseudorandom int value between zero and n drawn from the random number generator's sequence.

Throws

The nextInt() method throws IllegalArgumentException, if n is not positive.

Example 2

import java.util.Random;

public class JavaRandomNextIntExample2 {
static int j=1;
public static void main(String[] args) {
        Random random = new Random();
for (int i=1;i<8;i++) {
//return the next pseudorandom Integer value
Integer  val =random.nextInt(i);
System.out.println(j++ +". Random intvalue : "+val+" ");
        }
    }
}

Test it Now

Output:

1. Random intvalue : 0 
2. Random intvalue : 1 
3. Random intvalue : 0 
4. Random intvalue : 3 
5. Random intvalue : 1 
6. Random intvalue : 0 
7. Random intvalue : 0

Example 3

import java.util.Random;
import java.util.Scanner;
import java.util.concurrent.ArrayBlockingQueue;

public class JavaRandomNextIntExample3 {
static int j=1;
public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
System.out.print("Enter number of players.");
int capacity = scanner.nextInt();
ArrayBlockingQueue<String> queue = new ArrayBlockingQueue<String>(capacity);
System.out.println("Enter name of " + capacity + " Players.");
for (int i = 0; i < capacity; i++) {
System.out.print(j++ + " ");
            String str = scanner.next();
queue.add(str);
        }
j = 1;
        Random random = new Random();
for (String xyz : queue) {
            Integer val = random.nextInt(capacity);
System.out.println(j++ +". " +xyz+" will have "+val+" bonus points.");
        }
    }
}

Test it Now

Output:

Enter number of players.3
Enter name of 3 Players.
1 Sukla
2 Mukta
3 Amar
1. Sukla will have 0 bonus points.
2. Mukta will have 1 bonus points.
3. Amar will have 2 bonus points.

Example 4

import java.util.Random;

public class JavaRandomNextIntExample4 {
public static void main(String[] args) {
        Random random = new Random();
//return the next pseudorandom integer value
Integer val = random.nextInt(0);
System.out.println("Random Integer value : "+val);
    }
}

Test it Now

Output:

Exception in thread "main" java.lang.IllegalArgumentException: bound must be positive
	atjava.util.Random.nextInt(Random.java:388)
	at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9)

Note: The bound value must be positive else it will give IllegalArgumentException.

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