Program to Count the Total Number of Punctuation Characters Exists in a String

Q. Program to count the total number of punctuation characters exists in a string.

In this program, all the subsets of the string need to be printed. The subset of a string is the character or the group of characters that are present inside the string. For example, all possible subsets of a string "FUN" will be F, U, N, FU, UN, FUN.

Algorithm

Define a string.
If any character in the string is matched with (! , . , ' , - , " , ? , ; ) , increment the count by 1.
Print the count.

Complexity:

O(n)

Solution

Python

count = 0;
str = "Good Morning! Mr. James Potter. Had your breakfast?";
for i in range (0, len (str)): 
    #Checks whether given character is a punctuation mark
    if str[i] in ('!', "," ,"\'" ,";" ,"\"", ".", "-" ,"?"):
        count = count + 1;
        
print ("Total number of punctuation characters exists in string: ");
print (count);

Output:

Total number of punctuation characters exists in string: 
4

C

#include <stdio.h>
int main ()
{
   int i, countPuncMarks = 0;
   char str [] = "Good Morning! Mr. James Potter. Had your breakfast?";

    //Checks whether given character is punctuation mark
   for(i = 0; i < strlen(str); i++){
       if(str[i] == '!' || str[i] == ',' || str[i] == ';' || str[i] == '.' || str[i] == '?' || 
       str[i] == '-' || str[i] == '\'' || str[i] == '\"' || str[i] == ':') {
                countPuncMarks++;
            }
   }
   printf("Total number of punctuation characters exists in string : %d ",countPuncMarks);
   return 0;
}

Output:

Total number of punctuation characters exists in string: 4

JAVA

public class punctuation {
    public static void main (String [] args) {
        //Stores the count of punctuation marks
        int countPuncMarks = 0;
        String str = "Good Morning! Mr. James Potter. Had your breakfast?";
        for (int i = 0; i < str.length(); i++) {
                //Checks whether given character is punctuation mark
            if(str.charAt(i) == '!' || str.charAt(i) == ',' || str.charAt(i) == ';' || str.charAt(i) == '.' ||        str.charAt(i) == '?' || str.charAt(i) == '-' ||
                    str.charAt(i) == '\'' || str.charAt(i) == '\"' || str.charAt(i) == ':') {
                countPuncMarks++;
            }
        }
        System.out.println("Total number of punctuation characters exists in string: " +        countPuncMarks);
    }
}

Output:

Total number of punctuation characters exists in string: 4

C#

using System;                
public class Program
{
    public static void Main ()
    {
        //Stores the count of punctuation marks
        int countPuncMarks = 0;
        string str = "Good Morning! Mr. James Potter. Had your breakfast?";
        for (int i = 0; i < str.Length; i++) {
         //Checks whether given character is punctuation mark
         if(str[i] == '!' || str[i] == ',' || str[i] == ';' || str[i] == '.' || str[i] == '?' || str[i] == '-' ||
                    str[i] == '\'' || str[i] == '\"' || str[i] == ':') {
                countPuncMarks++;
            }
        }
        Console.WriteLine("Total number of punctuation characters exists in string: " + countPuncMarks);
    }
}

Output:

Total number of punctuation characters exists in string: 4

PHP

<!DOCTYPE html>
<html>
<body>
<?php
    //Stores the count of punctuation marks
    $count = 0;
    $str = "Good Morning! Mr. James Potter. Had your breakfast?";
    for($i = 0; $i < strlen($str); $i++) {
        //Checks whether given character is punctuation mark
        if($str[$i] == '!' || $str[$i] == ',' || $str[$i] ==     ';' || $str[$i] == '.'  || $str[$i] == '?' || $str[$i] == '-' || $str[$i] == '\'' || $str[$i] ==   '\"' || $str[$i] == ':') {
                $count++;
            }
        }
    echo "Total number of punctuation characters exists in string : ";
    echo $count;
?>
</body>
</html>

Output:

Total number of punctuation characters exists in string: 4

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Q. Program to count the total number of punctuation characters exists in a string.

Algorithm

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