Python Program to check Armstrong Number

Suppose we have a given number, "K", and we have to check whether the given number is an Armstrong number or not. In this tutorial, we will learn how to identify the given number is an Armstrong number or not using Python.

Definition:

A positive number of "p" number of digits is called an Armstrong number of order n (order is the number of digits) if:

Example:

Input:  407
Output: Yes, 407 is an Armstrong number
Solution:
(4 * 4 * 4) + (0 * 0 * 0) + (7 * 7 * 7) = 407 
Input:  1634
Output: Yes, 1634 is an Armstrong number
Solution:
(1 * 1 * 1) + (6 * 6 * 6) + (3 * 3 * 3) + (4* 4 * 4) = 1634
Input:  253
Output: No, 253 is not an Armstrong number
Solution:
(2 * 2 * 2) + (5 * 5 * 5) + (3 * 3 * 3) = 160
Input:  1
Output: Yes, 1 is an Armstrong number
Solution:
(1* 1) = 1

Example:

def power_1(A, B):
      
    if B == 0:
        return 1
    if B % 2 == 0:
        return power_1(A, B // 2) * power(A, B // 2)
          
    return A * power(A, B // 2) * power(A, B // 2)
  
# Function for calculating "order of the number"
def order_1(A):
  
    # Variable for storing the number
    N = 0
    while (A != 0):
        N = N + 1
        A = A // 10
          
    return N
  
# Function for checking if the given number is Armstrong number or not
def is_Armstrong(A):
      
    N = order_1(A)
    temp_1 = A
    sum_1 = 0
      
    while (temp_1 != 0):
        R_1 = temp_1 % 10
        sum_1 = sum_1 + power_1(R_1, N)
        temp_1 = temp_1 // 10
  
    # If the above condition is satisfied, it will return the result
    return (sum_1 == A)
  
# Driver code
A = int(input("Please enter the number to be checked: "))
print(is_Armstrong(A))

Output:

1#
Please enter the number to be checked:  0
True
2#
Please enter the number to be checked:  123
False
3#
Please enter the number to be checked:  1634
True