Seven Segment Display Problem in JavaSeven segments display is an output display device. It provides a way to display information in the form of images, text, or decimal numbers. It is an alternative to complex dot matrix displays. Seven segment displays are widely used in digital or electronic devices like calculators, watches, game consoles, electronic meters, etc. In this section, we will discuss how to represent a number in sevensegment display in Java. What is seven segment display?It is a display device that forms a number using seven segments of LEDs (horizontal and vertical bars) that look like the number 8. These seven segments can form any number from 0 to 9. For example, consider the following figure. Working of Seven SegmentThe following table depicts the digits and corresponding segment code where 0 represents no power supply and 1 represents power supplied.
We observe that the minimum number of segments to represent a digit is 2. Before moving to the solution, first, we will see the Java program that displays the sevensegment digits. Java Program to Represent a Digit in Seven Segment FormThere are the following two ways to print digits in sevensegment form:
Using switch CaseIt is the naïve approach to print digit as seven segment display. In the following Java program, we have read a digit from the user and switched the corresponding case that prints the digit as seven segment display. DisplaySevenSegment.java Output 1: Output 1: Let's see another way to print digits in seven segment display. Using Hexadecimal EncodingIn the following Java program, we have used hexadecimal encoding to represent a digit in seven segment form. The following table depicts the same. In the table on represent, 1 and off represents 0. Let's implement the above logic in a Java program. DisplayDigitSevenSegment.java Output: Problem StatementThe problem is divided into the following two subproblems.
Let's discuss the subproblems one by one. Subproblem 1We have given an Ndigit number and we have to find the minimum number of segments required to display each digit. Sum up all the segments and return the total number of segments to display the Ndigit number. Example: Suppose, N=6 (number of digits) and s="234567". The minimum number of segments requires to represent digit 2 is 5. The minimum number of segments requires to represent digit 3 is 5. The minimum number of segments requires to represent digit 4 is 4. The minimum number of segments requires to represent digit 5 is 5. The minimum number of segments requires to represent digit 6 is 6. The minimum number of segments requires to represent digit 7 is 3. So, the total number of segments that we require is 28 (5 + 5 + 4 + 5 + 6 + 3). Let's implement the above approach in a Java program. SegmentSum.java Output: Subproblem 2In this problem, we have given an array of natural numbers. The task is to find which natural number uses the minimum number of segments to display a number. There might be a condition in which multiple natural numbers have the minimum number of segments, in such a case, the output will be the number that has the smallest index. For example, consider the following array. arr[] = {22, 46, 88, 12, 67, 90, 23, 55, 61} 22 > 5+5 = 10 46 > 4+6 = 10 88 > 7+7 = 14 12 > 2+5 = 7 67 > 6+3 = 9 90 > 6+6 = 12 23 > 5+5 = 10 55 > 5+5 = 10 61 > 5+5 = 8 We observe that number 12 uses the minimum number of segments to display the number. So, the output will be 12. Java Program to Find Element Using Minimum Segments in Seven Segments DisplayIn the following Java program, we have stored the number of segments of each digit. After that, we have defined the two functions one Computes segments for the digits and the second function computes the minimum segment for the entire number. After that, we have compared each digit's segments to each other and return the number that uses the minimum number of segments. Let's see the Java program for the same. SevenSegment.java Output: 12 Complexity The time complexity for the above approach is O(n * log_{10}n) and the space complexity is O(1).
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