Java Collections disjoint() Method

The disjoint() method of Java Collections class is used to check whether two specified collections are disjoint or not. It returns true if the two specified collections have no elements in common.

Syntax

Following is the declaration of disjoint() method:

Parameter

Parameter	Description	Required/Optional
c1	It is the first collection.	Required
c2	It is the second collection.	Required

Returns

The disjoint() method returns true if the two specified collections have no elements in common.

Exceptions

The disjoint() method throws the following exceptions-

NullPointerException- It throws this exception if either of the collection is null or if one collection contains a null element and null is not an eligible element for the other collection. (Optional).

ClassCastException- It throws this exception if one collection contains an element that is of a type which is not eligible for the other collection. (Optional).

Compatibility Version

Java 1.5 and above.

Example 1

import java.util.*;
public class CollectionsDisjointExample1 {
	public static void main(String[] args) {
		//Create two lists    
	      List<String> list1 = new ArrayList<String>(5);
	      List<String> list2 = new ArrayList<String>(10);
	      //Add elements in both lists
	      list1.add("Java");
	      list1.add("PHP");
	      list1.add("JavaScript");
	      list2.add("C++");
	      list2.add("C");
	      list2.add("C#");      
	      //Check elements in both List
	      //It returns true if no elements are common.
	      boolean iscommon = Collections.disjoint(list1, list2 );
	      System.out.println("Output: "+iscommon);   
	      }
}

Test it Now

Output:

Output: true

Example 2

package myPackage;
import java.util.*;
public class CollectionsDisjointExample2 {
	public static void main(String[] args) {
		//Create two lists    
		List<Integer> list = Arrays.asList(10, 20, 30, 40);
            List<Integer> list2 = Arrays.asList(10, 20, 30, 4, 5, 6);
            boolean b = Collections.disjoint(list, list2);
            System.out.println("Output: "+b); 
	      }
}

Test it Now

Output:

Output: false

Example 3

package myPackage;
import java.util.*;
public class CollectionsDisjointExample3 {
	public static void main(String[] args) {
		  //Create two lists    
		  List<String> list1 = new ArrayList<String>(); 
	        list1.add("Facebook");
	        list1.add("Instagram");
	        list1.add("Twitter");	        
	        List<String> list2 = new ArrayList<String>();
	        list2.add("Whatsapp");
	        list2.add("Hike");
	        list2.add("Skype");
	        //Check common elements in both lists
	        boolean isCommon = Collections.disjoint(list1,list2);
	        if(isCommon) 
	        	   System.out.println("Lists Must Have Nothing In Common!");
	        	  else
	        	   System.out.println("Lists Must Have Something In Common!");
	        //Add one elements in the List1 and check for common elements again
	        list1.add("Whatsapp");
	        isCommon = Collections.disjoint(list1,list2);
	        if(isCommon) 
	        	   System.out.println("Lists Must Have Nothing In Common!");
	        	  else
	        	   System.out.println("Lists Must Have Something In Common!"); 
	        }
}

Test it Now

Output:

Lists Must Have Nothing In Common!
Lists Must Have Something In Common!

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Java Collections disjoint() Method

Syntax

Parameter

Returns

Exceptions

Compatibility Version

Example 1

Example 2

Example 3

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