Program to print the elements of an array present on odd position

Q. Program to print the elements of an array present on odd position.

Explanation

In this program, we need to print the elements of the array which are present in odd positions. This can be accomplished by looping through the array and printing the elements of an array by incrementing i by 2 till the end of the array is reached.

Program to convert a given binary tree to doubly linked list

In the above array, the elements which are on odd positions are a, c and e.

Algorithm

Declare and initialize an array.
Calculate the length of the declared array.
Loop through the array by initializing the value of variable "i" to 0 then incrementing its value by 2, i.e., i=i+2.
Print the elements present in odd positions.

Solution

Python

#Initialize array 
arr = [1, 2, 3, 4, 5]; 
 
print("Elements of given array present on odd position: ");
#Loop through the array by incrementing the value of i by 2 

for i in range(0, len(arr), 2):
    print(arr[i]); 

Output:

Elements of given array present on odd position: 
1
3
5

C

#include <stdio.h>
 
int main()
{
    //Initialize array 
    int arr[] = {1, 2, 3, 4, 5}; 
    
    //Calculate length of array arr
    int length = sizeof(arr)/sizeof(arr[0]);
    
    printf("Elements of given array present on odd position: \n");
    //Loop through the array by incrementing value of i by 2 
    for (int i = 0; i < length; i = i+2) { 
        printf("%d\n", arr[i]); 
    } 
    return 0;
}

Output:

Elements of given array present on odd position: 
1
3
5

JAVA

public class OddPosition {
    public static void main(String[] args) {
        
        //Initialize array 
        int [] arr = new int [] {1, 2, 3, 4, 5}; 
        
        System.out.println("Elements of given array present on odd position: ");
        //Loop through the array by incrementing value of i by 2 
        for (int i = 0; i < arr.length; i = i+2) { 
            System.out.println(arr[i]); 
        }  
    }
}

Output:

Elements of given array present on odd position: 
1
3
5

C#

 using System;
                    
public class OddPosition
{
    public static void Main()
    {
        //Initialize array 
        int [] arr = new int [] {1, 2, 3, 4, 5}; 
        
        Console.WriteLine("Elements of given array present on odd position: ");
        //Loop through the array by incrementing value of i by 2 
        for (int i = 0; i < arr.Length; i = i+2) { 
            Console.WriteLine(arr[i]); 
        } 
    }
}

Output:

Elements of given array present on odd position: 
1
3
5

PHP

<!DOCTYPE html>
<html>
<body>
<?php
//Initialize array 
$arr = array(1, 2, 3, 4, 5); 
 
print("Elements of given array present on odd position: <br>");
//Loop through the array by incrementing value of i by 2 
for ($i = 0; $i < count($arr); $i = $i+2) { 
    print($arr[$i] . "<br>"); 
}  
?>
</body>
</html>

Output:

Elements of given array present on odd position: 
1
3
5

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Q. Program to print the elements of an array present on odd position.

Explanation

Algorithm

Solution

Python

C

JAVA

C#

PHP

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