C Array Test 3

The correct option is (b).

Explanation:

In program the statement int arr[size]; produces an error, because we cannot initialize the size of array dynamically. Constant expression is required for initialize the size of array. For Example: int arr[20];

Therefore the code is erroneous since the statement declaring an array is invalid.

The correct option is (a).

Explanation:

Yes, both mean two different things. 'arr' gives the address of first int, whereas the '&arr' gives the address of array of ints.

Therefore the expression '&arr' and 'arr' are different for an array of 15 integers.

The correct option is (b).

Explanation:

No, both the declarations are same. It is a prototype for function fun() that accepts one integer array as parameter and an integer value is return.

The correct option is (c).

Explanation:

Step 1: int arr[2]={20}; The variable arr[2] is declared as an integer array with size of '3' and it's first element is initialized with value '20'(means arr[0]=20)

Step 2: printf("%d\n", 0[arr]); It prints the first element value of variable 'arr'.

Therefore the output of the program is 20.

The correct option is (a).

Explanation:

Step 1: int arr[] = {10, 11, 12, 15, 23}; The variable 'arr' is declared as an integer array and initialized.

Step 2: printf("%u, %u\n", arr, &arr); Here, the base address of the array is 65486.

Hence the arr, &arr is pointing towards the base address of the array arr.

Hence the output of the program is 65486, 65486