Java program to print the following pattern 4

Java program to print the following pattern

Algorithm:

STEP 1: START
STEP 2: SET lines=8
STEP 3: DEFINE i, j
STEP 4: SET i=1.REPEAT STEP 5 to 14 UNTIL i
STEP 5: SET j=1
STEP 6: REPEAT STEP 7 and 8 UNTIL j <=(lines/2)
STEP 7: IF j is equals to i PRINT j
ELSE IF i is greater than 4 and j equals (lines-i) PRINT j
ELSE PRINT " "
STEP 8: j = j + 1
STEP 9: j = j - 2
STEP 10: REPEAT STEP 11 and 12 UNTIL j > 0
STEP 11: IF j is equals to i PRINT j
ELSE IF i is greater than 4 and j equals (lines-i) then PRINT j
ELSE PRINT " "
STEP 12: j = j - 1
STEP 13: PRINT a new line
STEP 14: i = i + 1
STEP 15: END

Program:

 public class pattern{
public static void main(String []args){

   int lines=8;
    int i,j;
    for(i=1;i<lines;i++){// this loop is used to print the lines
        for(j=1;j<=lines/2;j++){// this loop is used to print numbers
            if(i==j){
                System.out.print(j);
            }
            else if(i>4 && j==lines-i){
                System.out.print(j);
            }
            else{
               System.out.print(" ");
            }
        }
        j=j-2;
        while(j>0){ //this loop is used to print numbers
            if(i==j){
            System.out.print(j);
            }
            else if(i>4 && j==lines-i){
                System.out.print(j);
            }
            else{
                System.out.print(" ");
            }

            j--;
        }
        System.out.println("");
    }
     }
}

Output:

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