Time response of second order systemIn the above transfer function, the power of 's' is two in the denominator. That is why the above transfer function is of a second order, and the system is said to be the second order system. Time response of second order system with unit step From equation 1 For unit step the input is Now taking the inverse Laplace of above equation This equation can also be written as Transient response specification of second order systemThe performance of the control system are expressed in terms of transient response to a unit step input because it is easy to generate initial condition basically are zero. Following are the common transient response characteristics:
Delay TimeThe time required for the response to reach 50% of the final value in the first time is called the delay time. Rise TimeThe time required for response to rising from 10% to 90% of final value, for an overdamped system and 0 to 100% for an underdamped system is called the rise time of the system. Peak TimeThe time required for the response to reach the 1st peak of the time response or 1st peak overshoot is called the Peak time. Maximum overshootThe difference between the peak of 1st time and steady output is called the maximum overshoot. It is defined by Settling Time (t_{s})The time that is required for the response to reach and stay within the specified range (2% to 5%) of its final value is called the settling time. Steady State Error (e_{ss})The difference between actual output and desired output as time't' tends to infinity is called the steady state error of the system. Example  1When a secondorder system is subjected to a unit step input, the values of ξ = 0.5 and ωn = 6 rad/sec. Determine the rise time, peak time, settling time and peak overshoot. Solution:Given Rise Time: Peak Time: Settling Time: Maximum overshoot:
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