Aptitude Problems on Numbers Test Paper 216) The product of two numbers is 300, and the sum of their squares is 625. What are the numbers?
Answer: C Explanation: Let the numbers be x and y. xy = 300 So, (x+y)^{2} = x^{2} + y^{2} + 2xy 17) The difference between a twodigit number and the number obtained by interchanging the position of the digits is 45. What is the difference between digits of that number?
Answer: B Explanation: Let the number be = xy 18) When the numerator of a certain fraction is increased by 1 and the denominator by 2, it changes to ; but when the numerator is increased by 5 and the denominator by 1, the value of the fraction changes to . What is the original fraction? Answer: C Explanation: Let the fraction be . As per the question: As per the question: Solving equation ((1) and (2), we get: x + 3y = 16 So, x = 16  3y or x = 16 + 3y Put the value of x in equation (i) 3 (16 + 3y)  2y = 1 Now, put the value of Y in equation (i) 3x  2 * 7 = 1 19) The difference between a twodigit number and the number obtained by changing the positions of its digits is 36. What is the difference between the two digits of that number?
Answer: B Explanation: Let the number be = xy So, the ten's digit is x and the unit's digit is y. As per the question: (10x + y)  (10y + x) = 36 20) A twodigit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. Find the number.
Answer: B Explanation: Let the ten's and unit digit be x and , respectively. 10x^{2} + 8 + 18x = 80 + x^{2} Ten's place= 2 Aptitude Problems on Numbers Test Paper 1 Aptitude Problems on Numbers Test Paper 2 Aptitude Problems on Numbers Test Paper 3 Problems on Numbers Concepts
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