## Aptitude Problems on Ages Test Paper 11) A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother? - 38 years
- 40 years
- 43 years
- 45 years
The Correct answer is (D)
Let the age of son = X years ∴Age of mother would be =2X As per question 20 years ago; 10 (X -20) = 2X - 20 10X - 200 = 2X - 20 10X - 2X= - 20 + 200 8X = 180 X== 22.5 years ∴Age of mother = 22.5 * 2 = 45 years 2) Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son? - 34, 9
- 33, 7
- 35, 5
- 36, 6
The Correct answer is (A)
Let age of son 4 years ago be = X So, age of man 4 years ago would be = 6X As per question after 16 years; 2* age of son = age of man 2(X + 4 +16) = (6X + 4 + 16) 2X +40 = 6X + 20 2X - 6X = 20 - 40 - 4X = - 20 X = 5 years ∴Present age of son = 5 + 4= 9 years Present age of man = 6X + 4= 6*5 + 4 = 30 +4 = 34 years
Apply formula; 3) The ratio of the ages of Minu and Meera is 4:2. If the sum of their ages is 6 years, find the ratio of their ages after 8 years. - 8:6
- 6:5
- 6:4
- 7:5
The Correct answer is (B)
Let the age of Minu is 4X and age of Meera 2X. As per question; 4X + 2X = 6 6X = 6 X = 1 ∴Minu's age = 4*1= 4 years Meera's age = 2*1= 2 years Ratio of their ages after 8 years; = (4+8): (2+8) = 12: 10 = 6:5 4) The ratio of the ages of Seeta and Geeta is 2:7. After 6 years, the ratio of their ages will be 1:2. What is the difference in their present ages? - 8 years
- 9 years
- 10 years
- 11 years
The Correct answer is (C)
Let the age of Seeta is 2X and age of Geeta 7X. As per question after 6 years; 4X +12 = 7X + 6 -3X = -6 X = 2 ∴Age of Seeta = 2 * 2 = 4 years Age of Geeta = 7 * 2 = 14 years Difference in their ages = 14 - 4 = 10 years 5) Ten years ago, the sum of ages of a father and his son was 34 years. If the ratio of present ages of the father and son is 7:2, find the present age of the son. - 12 years
- 11 years
- 10 years
- 8 years
The Correct answer is (A)
Let the present age of the father is 7X and present age of son is 2X. As per question, ten years ago; (7X - 10)+ (2X - 10) = 34 7X - 10 + 2X - 10= 34 9X = 34 + 20 9X = 54 X = 6 ∴Present age of son = 2 * 6= 12 years |