Profit and Loss Test Paper 416) By selling a property for Rs 45000 a person incurs a loss of 10%. Find the selling price to gain the profit of 15 %?
Answer: C Explanation: S.P = 45000 Apply formula: C.P = (100)/ (100 L %)) * S.P C.P = (100/ (10010))* 45000 Now, to gain the profit of 15%: Apply formula: S.P = ((100+P %) /100) * C.P S.P = ((100+15)/100) * 50000 S.P = 57500 17) A person purchases some article at the rate of 4 articles for rupees 5 and sells them at the rate of 5 articles for rupees 4. Find the total profit or loss in %.
Answer: B Explanation: The C.P of 4 article is rupees 5 and selling price of 5 article is rupees 4. Note: article ratio should be the same in both cases. i.e., Article price C.P = 4 5 S.P = 5 4 As the article is same in both the cases, we should make the article equal. To make article value equal, we need to multiply C.P with 5 and S.P with 4. The change made in Article should also be performed at a price to calculate the % profit or loss. i.e., Article price C.P = 4* 5 = 20 5* 5 = 25 S.P = 5 * 4= 20 4* 4 = 16 The difference between the price of C.P and S.P is 2516 = 9. Now, apply % formula: Profit or Loss % = ((difference between C.P and S.P)/ C.P) * 100 Note: if S.P > C.P = profit Here C.P = 25, and S.P = 16 So, Loss % = (9/25) * 100 = 36% Hence, the person incurs a loss of 36%. 18) A shopkeeper purchases some article at the rate of 2 articles for rupees 3 and purchases twice of the quantity at the rate of 3 articles for rupees 2. He sells them at the rate of 6 articles for rupees 7. Find the profit or loss %.
Answer: D Explanation: ATQ, A shopkeeper purchases an article at the rate of 2 for rupees 3, and again purchase twice of the quantity at the rate of 3 for rupees 2 and the selling price of the all articles is 6 for rupees 7. Here, the total articles are purchased in 2 times. i.e., Article price C.P 1 = 2 3 C.P 2 = 3 2 But the shopkeeper purchases double articles the second time. To satisfy the condition, we need to multiply the C.P 1 with 3 and C.P 2 with 4. The change made in Articles should also be performed at their price to calculate the % profit or loss. i.e., Article price C.P 1 = 3* 2 = 6 3* 3 = 9 C.P 2 = 4* 3 = 12 4* 2 = 8 Now, we can see that C.P 2's article = 2 * C.P 1's article i.e., Article price C.P = 18 17 S.P = 6 7 Note: the article should always be equal in S.P and C.P. To make it equal, multiply S.P with 3 and the change should also be made in the price. i.e., Article price C.P = 18 17 S.P = 3*6=18 3* 7 = 21 The difference between the price of C.P and S.P is 2117 = 4 Profit or Loss % = ((difference between C.P and S.P)/ C.P) * 100 19) A shopkeeper sells his goods at a profit of 10%. If he had purchased it at 20% less and sells it at rupees 10 more, he had a gain of 40%. Find the C.P of the goods.
Answer: A Explanation: Let the C.P of an article is 100. If the C.P is 80, then he earns a profit of 40% and sells the article at Rs 10 more than the previous price. That means if the C.P = 80, the S.P = 80+32 = 112............................ (ii) Compare equation 1 and 2, and we get the difference between S.P is = 2 Hence, the C.P of the article is = 100 * 5 = 500 20) The C.P of an article is equaled to the profit %, and a shopkeeper sells it in Rs 56. Find the C.P of the article.
Answer: A Explanation: C.P = Profit %, S.P = 56 (given) Apply formula: S.P = ((100 + Profit %)/100) * C.P 56 = ((100 + x)/100) * x Now calculate the factors. x^{2}+ 140x  40x 5600=0 x= 140 and +40. Aptitude Profit & Loss Test Paper 1 Aptitude Profit & Loss Test Paper 2 Aptitude Profit & Loss Test Paper 3 Aptitude Profit & Loss Test Paper 5 Profit & Loss Concepts
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