Area Aptitude Test Paper 416) The difference between the length and the perimeter of a rectangle is 100 cms. What is the breadth of the rectangle?
Answer: D Explanation: Let the length of the rectangle be 'x' and breadth of the rectangle be 'y' According to the question: 2(x + y)  x = 100 2x + 2y  x = 100 x + 2y = 100 From this we cannot find 'y' (breadth), so the given data is inadequate. 17) The sides of a rhombus are 10 cm in length, and one diagonal is 16 cm. The area of the rhombus is
Answer: A Explanation: When d_{1} and d_{2} are the diagonals of rhombus then, Squaring both sides 20^{2} = 16^{2} + d_{2}^{2} 400 = 256 + d_{2}^{2} d_{2}^{2} = 400  256 d_{2} = √144 d_{2} = 12 Area of rhombus =1/2( d_{1} × d_{2} ) =1/2 ( 16 × 12 )=96 cm^{2} 18) If each side of the square is increased by 50%, what will be the ratio between the new area and the original area of the square?
Answer: B Explanation: 19) The sides of a rectangular field are in the ratio 3: 4 and its area is 7500 m2. What is the cost of fencing it at 25 paise per meter?
Answer: A Explanation: Ratio between the sides of rectangle = 3: 4 Let the ratio constant be x then, Length = 3x and breadth = 4x Area = L x B 7500=3x × 4x=12x^{2} x=25 Length = 3 x 25 = 75 m, and Breadth = 4 x 25 = 100 m Perimeter = 2(75 + 100) = 2 x 175 = 350 m Cost of fencing 1 meter = 25 paise Cost of fencing 350 m = 350 x 25 = 8750 paise In rupees: Rs. 87.50 20) If the size of a tile is 9" by 9", how many tiles are required to cover a 12 ft. wide and 18 ft. long floor?
Answer: B Explanation: Area Aptitude Test Paper 1 Area Aptitude Test Paper 2 Area Aptitude Test Paper 3 Area Aptitude Test Paper 5 Area Aptitude Test Paper 6 Area Aptitude Test Paper 7 Area Aptitude Test Paper 8 Area Concepts
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