## Aptitude Time and Work Test Paper 311) A can do a piece of work in 6 days working 8 hours a day. B can do the same work in 4 days working 6 hours a day. If they work together 8 hours a day, in how many days they will do this work? - 3 days
- 3.5 days
- 2 days
- 2.5 days
The Correct answer is (C)
A can complete the work in, 6 x 8 = 48 hour B can complete the same work in = 4 x 6 = 24 hours A's one hour work = B's one hour work = (A +B)'s one hour work = They will complete So, the entire work will be completed in 1 ∗ Both work 8 hours a day so the number of days required to complete the work = = 2 days 12) A can finish a work in 6 days and B can finish the same work in 8 days. A and B charge Rs. 2800 for the work. If with the help of C they complete the work in 3 days, how much they will pay to C? - Rs. 350
- Rs. 345
- Rs. 340
- Rs. 320
The Correct answer is (A)
A's one hour work = B's one hour work = (A +B)'s one hour work = (A+B+C)'s one day work = Therefore, C's one day work = The ratio of A, B and C's wages will be equal to the ratio of work done by them in one day. A's wages: B's wages: C's wages = C's share of three days = 3 * C's share for one day = 3 ∗ (1 ∗ 2800) = 35024 13) 5 men undertook a piece of work and finished half the work in 18 days if two men drop out, in how many days the remaining work will be completed? - 30 days
- 32 days
- 34 days
- 36 days
The Correct answer is (A)
5 men completed half of the work in 18 days so the entire work will be completed in 36 days. 5 men' one day work will be = One man's one day work = Two men drop out, so the three men have to complete the remaining work. Three men's one day work will be = part of the work is completed by three men in one day Therefore, the remaining part of the work will be completed in = 30 Days. 14) If 5 workers can paint a house in 9 days, in how many days 3 workers can complete the same task? - 13 days
- 14 days
- 15 days
- 16 days
The Correct answer is (C)
Using formula: M1D1W2 =M2D2W1 We have = 5∗9∗W2 = 3∗D2∗W1 W2 = W1 as the task is the same in both the cases, so the amount of work to be done would be the same. Therefore, we have 5 ∗ 9 = 3 ∗ D2 45 = 3∗ D2 D2 15) A group of workers undertakes a task. They can complete the task in 30 days. If 5 of them did not turn for the work and the remaining workers complete the task in 40 days, find the original number of workers. - 25 days
- 23 days
- 21 days
- 20 days
The Correct answer is (D)
Let the original number of workers = X X workers can complete the work in 30 days. And (X - 50) complete the same task in 40 days.
W1=W2 as the task is the same in both the cases. Therefore, X * 30 = (X - 5) * 40 30 X = 40X - 200 200 = 40X -30X 200 = 10 X X Aptitude Time and Work Test Paper 1 Aptitude Time and Work Test Paper 2 Aptitude Time and Work Test Paper 4 Aptitude Time and Work Test Paper 5 Aptitude Time and Work Test Paper 6 Aptitude Time and Work Test Paper 7 Aptitude Time and Work Test Paper 8 Aptitude Time and Work Test Paper 9 Time and Work Concepts Next TopicTime and Work Test Paper 4 |