Aptitude Time and Work Test Paper 521) A can finish the job at the same time in which B and C together do it. If A and B together can finish the work in 10 days and C alone can do the work in 50 days, how many days B will take to complete the same job?
Answer: D Explanation: ATQ, The efficiency of A = B+C Now, A+B = 10 days Note: Assume the total work = LCM of the given days Take the LCM of days = LCM of (10 and 50) = 50 Note: One day work = (total work/ days) Now, C's one day work = 50/50 = 1 i.e., (A+B+C)'s one day work = 5+1=6 i.e., A+A = 6 A+B = 5, i.e., 3+B = 5 22) A and B working together can finish a work in 12 days, B and C working together can finish the work in 16 days. If A works for 5 days, B works for 7 days, and C completes the remaining work in 13 days, C alone can complete the work in how many days?
Answer: B Explanation: ATQ, A+B = 12 days Note: Assume the total work = LCM of the given days Take the LCM of days = LCM of (12 and 16) = 48 Note: One day work = (total work/ days) Now, (A+B)'s one day work = 48/12 = 4 unit As per the question: A works for 5 days That means total work done by (A+B) in 5 days Remaining work = 4826 = 22 unit work C alone can finish total work in [total work/ C's one day work] = [48/2] = 24 days. 23) A can finish a work in 10 days and B can finish the same work in 15 days. If they work alternatively, find the time taken to finish the job.
Answer: C Explanation: Note: Assume the total work = LCM of the given days Take the LCM of days = LCM of (10 and 15) = 30 Note: One day work = (total work/ days) Now, A's one day work = 30/10 = 3 unit That means A and B works 5 unit works in 2 days To complete the 30 work, multiply both sides with 6. Or, 12 days = 30 works 24) A, B, and C individually can finish a job in 10, 15, and 30 days respectively. If A starts the work and continues until the end, B and C work alternatively, in how many days work will be done?
Answer: D Explanation: Note: Assume the total work = LCM of the given days Take the LCM of days = LCM of (10, 15, and 30) = 30 Note: One day work = (total work/ days) Now, A's one day work = 30/10 = 3 unit ATQ, A work continuously and B and C works alternatively i.e., (A+B)'s one day work = 3+2 = 5 unit Or, 2 days work = 9 unit i.e., 2 days * 3 = 9 unit * 3 Hence, the work will be finished in 6+3/5 days or 6[3/5] days. 25) A can finish a work in 10 days, B can finish the same work in 15 days, and C can finish it in 30 days. All three start working together, but after some days A leaves the job, then after one day B also left the job. C completes the remaining job in 3 days. Find the number of working days of B.
Answer: B Explanation: Note: Assume the total work = LCM of the given days Take the LCM of days = LCM of (10, 15, and 30) = 30 Note: One day work = (total work/ days) Now, A's one day work = 30/10 = 3 unit Note: man * days = total work ATQ, (A+B+C) works 6 units work per day till D days, so their total work = 6 * D Or, 6*D + 3*1 + 1*3 = 30 (total work) So, A works for 4 days, B works for 4+1=5 days, and C works for 4+1+3= 8 days. Aptitude Time and Work Test Paper 1 Aptitude Time and Work Test Paper 2 Aptitude Time and Work Test Paper 3 Aptitude Time and Work Test Paper 4 Aptitude Time and Work Test Paper 6 Aptitude Time and Work Test Paper 7 Aptitude Time and Work Test Paper 8 Aptitude Time and Work Test Paper 9 Time and Work Concepts
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