C/C++ Tricky Programs

In this tutorial, we will explore some amazing tricky programs in C/C++ programming language.

In our daily lives, we may come across a variety of perplexing programs, perhaps during technical interviews, coding assessments, or C/C++ classes.

A number of these programmes are listed below:

1. A code for printing text that should be surrounded by double quote marks (" ").

We utilise quotes in the C++ programming language to indicate the beginning and end of the text to be printed. As a result, printing quotations " necessitates the use of a particular escape sequence. To print quotations in C++, we shall utilise the " symbol.

C++ Program:

// CPP code for printing double quotations
#include<iostream>
int main ()
{
std::cout << "\"javaTpoint\"";
return 0;
}

Output:

" javaTpoint "

Time Complexity will be O (1)
Auxiliary Space will be O (1)

2. To determine whether two numbers are equal without employing arithmetic or comparison operators.

The Bitwise XOR operator () is the easiest solution for this. Keep in mind that the XOR operator gives 0 for two equal values. To deal with this problem, we shall employ the XOR operator.

C Program:

// C code to determine whether two values are equal instead of using arithmetic or comparison operators
#include<stdio.h>
int main ()
{
// Taking two variables 
int a = 12;
int b = 12;
if ( !( a ^ b ) )
	printf ( " a is equal to b" );
else
	printf ( " a does not match b " );
return 0;
}

C++ Program:

// C++ code to determine whether two values are equal instead of using arithmetic or comparison operators 
#include <iostream>
using namespace std;
int main ()
{
// Taking two variables 
int a = 12;
int b = 12;
if ( !( a ^ b ) )
	cout << " a is equal to b ";
else
	cout << " a does not match b ";
	
return 0;
}

Output:

a is equal to b

Time Complexity will be O (1)
Auxiliary Space will be O (1)

3. Without using a semicolon, print all natural integers up to N. The concept of recursively calling the main function is used.

C++ Program:

// C++ code that prints all natural numbers up to N without the use of a semicolon.
#include<iostream>
using namespace std;

int N = 15;
int main ()
{
static int a = 9;
if ( cout << a << " " && a++ < N && main () )
{ }
return 0;
}

Output:

9 10 11 12 13 14 15

Time Complexity will be O (1)
Auxiliary Space will be O (1)

4. A Code to swap the values of two variables without the usage of a third variable.

C++ Program:

// C++ program to check if two numbers are equal
#include<bits/stdc++.h>
using namespace std;

int main ()
{
int a = 15;
int b = 30;

a = a + b;
b = a - b;
a = a - b;

cout << "A : " << a << "\n";
cout << "B : " << b << "\n";
return 0;
}

Output:

A : 30
B : 15

Time Complexity will be O (1)
Auxiliary Space will be O (1)

5. Without using a loop or condition, write a program to identify the maximum and minimum of two values.

The most basic trick is-

C++ Program:

// C++ code for obtaining the maximum and minimum of two values without the use of a loop or any condition.
#include<bits/stdc++.h>

int main ()
{
int p = 35, q = 26;
printf ( "maximum no = %d\n", ((p + q) + abs(p - q)) / 2);
printf ( "minimum no = %d", ((p + q) - abs(p - q)) / 2);
return 0;
}

Output:

maximum no = 35
minimum no = 26

Time Complexity will be O (1)
Auxiliary Space will be O (1)

6. In C, use the One's Complement () Operator to output an unsigned int's maximum value.

Below is how we use the one's complement operator to find an unsigned int's maximum value:

C Program:

// A C program that displays the largest value of an unsigned int.
#include<stdio.h>
int main ()
{
unsigned int maximum;
maximum = 0;
maximum = ~maximum;
printf ( "Maximum value : %u ", maximum );
return 0;
}

C++ Program:

// A C++ program that displays the largest value of an unsigned int.
#include <iostream>

int main ()
{
unsigned int maximum;
maximum = 0;
maximum = ~maximum;
   std::cout << "Maximum value : " << maximum;
return 0;
}

Output:

Maximum value : 4294967295

Time Complexity will be O (1)
Auxiliary Space will be O (1)

7. To compute the sum of two numbers without relying on the '+' operator. This is a simple mathematical approach. We already understand that a + b = - (-a-b). So this will serve as a ruse for us.

C++ Program:

// C++ code for displaying the sum of two numbers without the need for the + operator
#include<iostream>
using namespace std;
int main ()
{
int x = 15;
int y = 3;
int summation = -( -x - y );
cout << summation;
return 0;
}

Output:

Time Complexity will be O (1)
Auxiliary Space will be O (1)

8. Inside the if block, write code to check the condition.

C++ Program:

// CPP code that checks the condition inside the if block. It just validates the condition within the if block, i.e., cout << "Hello" returns a non-zero value,!(non-zero value) is false, so else is executed. As a result, theoretically, it merely performs the else block.
#include<iostream>

using namespace std;
int main ()
{
	if ( !( cout << "Hello" ) )
	cout << "Hello";
	else
	cout << " World";

	return 0;
}

Output:

Hello World

Time Complexity will be O (1)
Auxiliary Space will be O (1)

9. Code to divide an integer by 4 without using the '/' operator. The right shift operator (">>") is one of the effective methods for dividing an integer by 4.

C++ Program:

// CPP code for dividing a number by 4 without using '/'
#include<iostream>

using namespace std;
int main ()
{
int num = 4;
num = num >> 2;
cout << num;
return 0;
}

Output:

Time Complexity will be O (1)
Auxiliary Space will be O (1)

10. A code that verify the computer's endianness.

C Program:

// C code to determine whether the machine is little or big endian.
#include <stdio.h>
int main ()
{
unsigned int num = 1;
char *c = (char*) & num;
if (*c)
	printf ( "THE MACHINE IS LITTLE ENDIAN") ;
else
	printf ( "THE MACHINE IS BIG ENDIAN" );
return 0;
}

C++ Program:

// C++ code to determine whether the machine is little or big endian.
#include <iostream>
int main ()
{
unsigned int num = 1;
char *c = (char*) & num;

if (*c)
	std::cout << "THE MACHINE IS LITTLE ENDIAN";
else
	std::cout << "THE MACHINE IS BIG ENDIAN";

return 0;
}

Output:

THE MACHINE IS LITTLE ENDIAN

Time Complexity will be O (1)
Auxiliary Space will be O (1)

Conclusion:

C and C++ are programming languages used to develop programmes, games, database systems, and operating systems, among other things. While the names C and C++ are similar, their features and applications are not. C is a procedural programming language that does not support objects or classes. C++ is an enhanced version of C that supports object-oriented programming. Let's look at the distinctions between the C and C++ programming languages.

Dennis Ritchie invented it at Bell Laboratories in 1972. This machine-independent language was designed to be used in the development of tools for the Unix platform. It is now widely employed in a range of applications.

SIt is an extension of the standard C language that incorporates support for object-oriented programming and other features. C++ is a computer language that is close to low-level languages and is recognised as one of the fastest. C++ is a programming language used to develop complex, high-performance programmes.

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