Leap year program in C

First of all, it is important to know what is leap year? Generally, a year has 365 days in a year, but a leap year has 366 days which comes after four year. Below are some points related to leap year:

A leap year is a year, which is different than a normal year having 366 days instead of 365.
A leap year comes once in four years, in which February month has 29 days. With this additional day in February, a year becomes a Leap year.
Some leap years examples are - 1600, 1988, 1992, 1996, and 2000.
Although 1700, 1800, and 1900 are century years, not leap years.

Below conditions are used to check that year is a leap year or not.

Year must be divisible by 4
Year is divisible by 400 and not divisible by 100.

By putting these conditions in your code, you can check year is a leap year or not. If the above conditions are satisfied, the year will be leap year. These conditions can be put with if-else or with && (and) and || (Or).

How to find leap year using C programming?

With the help of a C program, we will make easy to find a leap year.

Example

See the below example in which we check a leap year by taking input from user:

#include<stdio.h>
#include<conio.h>
void main() {
	int year;
	printf("Enter a year: ");
	scanf("%d", &year);
	if(((year%4==0) && ((year%400==0) || (year%100!==0))
	{
		printf("%d is a leap year", &year);
	} else {
		printf("%d is not a leap year", &year);
	}
	getch();
}

Output

See the below outputs for different input values:

Test 1:

Enter a year: 2004
2004 is a leap year

Test 2:

Enter a year: 1700
1700 is not a leap year

Example

In this below example, we will find the leap years between the range of two years like 2000 to 2020. See the below example:

#include<stdio.h>
#include<conio.h>
void main() {
	int startYear, endyear, i;
	printf ("Enter a year to start searching the leap years: ");
	scanf ("%d", &startYear);
	printf ("Enter a year to end the search of leap years: ");
	scanf ("%d", &endyear);
	printf ("Leap Years between %d to %d are: \n", &startYear, &endYear);
	for (i= startYear; i<= endYear, i++) 
	{
	     if(((i%4==0) && ((i%400==0) || (i%100!==0))
	     {
		  printf("%d \n", &i);
	     } 
	}
	getch();
}

Output

See the below output:

Enter a year to start searching the leap years: 1950
Enter a year to end the search of leap years: 2020
Leap years between 1990 to 2020 are:
1992
1996
2000
2004
2008
2012
2016
2020

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