C++ Math fma()

The function computes the expression x*y+z without losing its precision in any intermediate result.

Suppose numbers are x,y and z:

fma(x,y,z) = x*y+z;
Syntax
float fma(float x, float y, float z); double fma(double x, double y, double z); long double fma(long double x, long double y, long double z); double fma(type1 x,type2 y,type3 z);
Note: If any argument is long double type, then the return type is promoted to long double. If not, then the return type is promoted to double.
Parameter
x: The value which is to be multiplied.
y: The value which is to be multiplied with x.
z: The value which is to be added with the product of x and y.
Return value
It returns the result of x*y+z.
Example 1
Let's see the simple example.
#include <iostream> #include<math.h> using namespace std; int main() { int x= 2; int y=3; int z=4; std::cout << "Values of x,y,z are :" <<x<<","<<y<<","<<z<< std::endl; cout<<"fma(x,y,z) : "<<fma(x,y,z); return 0; }
Output:
Values of x,y,z are :2,3,4 fma(x,y,z) : 10
In this example, fma() function computes the result of x*y+z and returns the value 10.

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