std::minmax() and std::minmax_element() in C++ STL

We are already aware that the C++ programming language has a Standard Template Library which is vast like an ocean and has many pre-defined functionalities. To get the answer of which among the array elements passed either as an input by the user or pre-defined by the testers/developers is maximum or minimum amongst them, we use the standard minimum function or the entire function.

It might get a little overwriting or using the code, again and again, to know both values at a time. So C++ STL has a solution for us in the form of std minmax() and minmax_element functions. Both functions accept parameters in the form either variables, which are of any natural numbers, integers and also an array of elements.

C++ Code for minmax() Function

// Here, we are writing down the C++ programming language to demonstrate 
// the concept of std::minmax() and std::minmax_element() in C++ STL
#include<iostream>
#include<algorithm>
using namespace std;

int main()
{
	
// the below code snippet implements declaring the pair
// which is useful in catching the return value thrown after operations
pair<int, int> mnmx;

// the below code snippet helps us with using min and max functions passed 
// as two parameters
mnmx = minmax(63, 33);
	
// the below code snippet helps us with using min and max functions passed 
// as two parameters and printing them down on our output screens
cout << "minimum value is : ";
cout << mnmx.first;
cout << "\nmaximum value is : ";
cout << mnmx.second ;
	
// the below code snippet helps us with using min and max functions passed 
// as two parameters here, they are being given as the array of elements
mnmx = minmax({12, 15, 11, 16, 13});
	
// the below code snippet helps us with using min and max functions passed 
// as two parameters and printing them down on our output screens
cout << "\nminimum value: ";
cout << mix.first;
cout << "\nmaximum value  : ";
cout << mnmx.second;
	
}

Output:

/ tmp / 1Lj mBg VyK h.o
The minimum value is : 33
The maximum value is : 63
minimum value : 11
maximum value  : 16

C++ Code for minmax_element() Function

// Here, we are writing down the C++ programming language to demonstrate 
// the concept of std::minmax() and std::minmax_element() in C++ STL
#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;

int main()
{
	
	// the below code snippet helps us with vectors being passed as the 
	// data type integer and values ranging from only single integers
	vector<int> vi = { 15, 13, 14, 14, 13, 15, 13 };
		
		
	// the below code snippet helps us with declaring the pointer variable
	// of integer data type where one vector being iterator other is a maxx
	// these pointer variables return us a value which will then be caught
	pair<vector<int>::iterator, vector<int>::iterator> mnmx;
		
	// using minmax_element() to find
	// minimum and maximum element
	// between 0th and 3rd number
	mnmx = minmax_element(vi.begin(), vi.begin() + 14);
		

	// the below code snippet helps us with using min and max functions 
	//passed 
   // as two parameters and printing their positions down on our output 
   //screens
	cout << "position of the minimum value obtained after operating is : ";
	cout << mnmx.first - vi.begin() << endl;
		
	cout << "position of the maximum value obtained after operating is : ";
	cout << mnmx.second - vi.begin() << endl;
		
	cout << endl;
		

	
	// here, we are using the duplicates
	// the below code snippet prints us 11 and 15 respectively as outputs
	
	mnmx = minmax_element(vi.begin(), vi.end());
		
	// the below code snippet helps us with using min and max functions 
	//passed 
   // as two parameters and printing them down on our output screens

	cout << "position of the minimum value obtained after operating is : ";
	cout << mnmx.first - vi.begin() << endl;
		
	cout << "position of the maximum value obtained after operating is : ";
	cout << mnmx.second - vi.begin()<< endl;
	
	
	
}

Output:

/ tmp /1 LjmB gVy Kh.o
position of the minimum value obtained after operating is : 7
position of the maximum value received after working is : 10

position of the minimum value obtained after operating is : 1
position of the maximum value received after working is : 5

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