C++ Math fmin()

The function returns the minimum value between two numbers.

Conditions:

Consider two numbers 'x' and 'y'.

If(x: It returns x.
If(x>y): It returns y.
If(x=nan): It returns y.
If(y=nan):It returns x.

Syntax
float fmin(float x, float y); double fmin(double x, double y); long double fmin(long double x, long double y); promoted fmin(Arithmetic x, Arithmetic y);
Note: If any argument has an integral type, then it is cast to double. If any other argument is long double, then it is cast to long double.
Parameter
(x,y): Values among which the minimum value is to be calculated.
Return value
It returns the minimum value between two numbers.
Example 1
Let's see a simple example.
#include <iostream> #include<math.h> using namespace std; int main() { float x=1.1; float y=2.1; std::cout <<"Values of x and y are :"<<x<<","<<y<< std::endl; cout<<"Minimum value is :"<<fmin(x,y); return 0; }
Output:
Values of x and y are :1.1,2.1 Minimum value is :1.1
In this example, value of x is less than the value of y.Therefore, fmin() function returns the value of x.
Example 2
Let's see a simple example when one of the value is nan.
#include <iostream> #include<math.h> using namespace std; int main() { float x=10.1; double y=NAN; std::cout <<"Values of x and y are :"<<x<<","<<y<< std::endl; cout<<"Minimum value is :"<<fmin(x,y); return 0; }
Output:
Values of x and y are :10.1,nan Minimum value is :10.1
In this example, value of y is nan. Therefore, the value of x is returned.

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