# Line slope calculator 6x+5y=48

**Straight line given by points A[3; 6] and B[8; 0]**

## Calculation:

**Slope-intercept form of line:**y = -1.2x+9.6

**Canonical form of the line equation:**6x+5y-48 = 0

**Parametric form of the line equation:**

x = 5t+3

y = -6t+6 ; t ∈ R

**Slope:**m = -1.2

**Slope angle of line: φ =**-50°11'40″ = -0.8761 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 9.6

**Distance line from the origin:**d

_{0}= 6.1458

**The length of the segment AB: |AB| =**7.8102

**Vector: AB =**(5; -6)

**Normal vector: n =**(6; 5)

**Midpoint of the segment AB: M =**[5.5; 3]

**Perpendicular Bisector equation:**5x-6y-9.5 = 0

**Vector OA = (3; 6) ; |OA| = 6.7082**

**Vector OB = (8; 0) ; |OB| = 8**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 63°26'6″ = 1.1071 rad**