# Permutation and Combinations:

## Permutation:

Any arrangement of a set of n objects in a given order is called Permutation of Object. Any arrangement of any r ≤ n of these objects in a given order is called an r-permutation or a permutation of n object taken r at a time.

It is denoted by P (n, r)
P (n, r) = Theorem: Prove that the number of permutations of n things taken all at a time is n!.

Proof: We know that Example: 4 x np3=n+1P3

Solution: 4 x  4 (n-2) = (n+1)
4n - 8 = n+1
3n = 9
n = 3.

## Permutation with Restrictions:

The number of permutations of n different objects taken r at a time in which p particular objects do not occur is The number of permutations of n different objects taken r at a time in which p particular objects are present is Example: How many 6-digit numbers can be formed by using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8 if every number is to start with '30' with no digit repeated?

Solution: All the numbers begin with '30.'So, we have to choose 4-digits from the remaining 7-digits.

∴ Total number of numbers that begins with '30' is
7P4 = =840.

## Permutations with Repeated Objects:

Theorem: Prove that the number of different permutations of n distinct objects taken at a time when every object is allowed to repeat any number of times is given by nr.

Proof: Assume that with n objects we have to fill r place when repetition of the object is allowed.

Therefore, the number of ways of filling the first place is = n
The number of ways of filling the second place = n
.............................
.............................
The number of ways of filling the rth place = n
Thus, the total number of ways of filling r places with n elements is
= n. n. n..............r times =nr.

## Circular Permutations:

A permutation which is done around a circle is called Circular Permutation. Example: In how many ways can get these letters a, b, c, d, e, f, g, h, i, j arranged in a circle?

Solution: (10 - 1) = 9! = 362880

Theorem: Prove that the number of circular permutations of n different objects is (n-1)!

Proof: Let us consider that K be the number of permutations required.

For each such circular permutations of K, there are n corresponding linear permutations. As shown earlier, we start from every object of n object in the circular permutations. Thus, for K circular permutations, we have K...n linear permutations. ## Combination:

A Combination is a selection of some or all, objects from a set of given objects, where the order of the objects does not matter. The number of combinations of n objects, taken r at a time represented by nCr or C (n, r). Proof: The number of permutations of n different things, taken r at a time is given by As there is no matter about the order of arrangement of the objects, therefore, to every combination of r things, there are r! arrangements i.e., Example: A farmer purchased 3 cows, 2 pigs, and 4 hens from a man who has 6 cows, 5 pigs, and 8 hens. Find the number m of choices that the farmer has.

The farmer can choose the cows in C (6, 3) ways, the pigs in C (5, 2) ways, and the hens in C (8, 4) ways. Thus the number m of choices follows: ### Feedback   