Split a Circular List into 2 HalvesIntroductionA Circular linked list where the last node points back to the first node, forming a loop. Every node in the circular linked list has a data element and a pointer to the next node. In this article, we will be splitting a circular linked list into two halves, an operation in linked list manipulation where we will use Floyd's Cycle-finding algorithm. Key PointsNote: Each element in a circular linked list is called a node. A node consists of two parts: data and a pointer to the next node in the list.Circularity: The key characteristic of a circular linked list is that the last node's reference points back to the first node, creating a loop. This ensures that there is no real end to the list. Problem StatementWe have a circular linked list of length n. We have to split the original circular linked list into two halves Input Original Circular Linked List Output First Half Second Half Explantation The original number of nodes is 5, separated into 3 and 2 nodes. The given nodes are in odd numbers so that the first Half will contain the extra node than the second Half. AlgorithmTo split a circular linked list in C++ using Floyd's Cycle-Finding Algorithm (also known as the "Tortoise and Hare" algorithm), you can follow these steps:
Implementation C++Output: The above code uses Floyd's cycle-finding algorithm to find the midpoint of the circular linked list and then splits it into two halves. Note: As an example in this article, if the Inputs are in an odd number of nodes, the first Half will contain one Extra node.ConclusionIn conclusion, splitting a circular linked list into two halves we have used can be a useful operation when dealing with data manipulation and algorithms. We can divide the list into two equal parts by finding the middle node and breaking the circular reference. |
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